# e4.3TextProgress.py
import time

scale = 50
print("执行开始".center(scale // 2, '-'))
t = time.clock()
for i in range(scale + 1):
    a = '*' * i
    b = '.' * (scale - i)
    c = (i / scale) * 100
    t -= time.clock()
    print("\r{:^3.0f}%[{}->{}]{:.2f}s".format(c, a, b, -t), end='')
    time.sleep(0.05)
print("\n" + "执行结束".center(scale // 2, '-'))
